yes the answer on the back of the book is 0C.
thanks for your post now i know how calculated if the ice is melted or not.
i don't know why i didn't think of it before.
now i'll try to write down my equations
Thanks all for your help, but i can't get the answer to my problem.
i'm using this values
ICE
$
T_i = -15C = 258.15K \\
m_i = 100g = 0.1Kg \\
c_i = 2220 \frac{J}{Kg*K} \\
L_i = 333 \frac{KJ}{Kg}
$
Water
$
T_i = 25C = 298.15K \\
m_w = 200g = 0.2Kg \\
c_w = 4190...
Yes i consider that. but how do i know all the ice is melted?
if all the ice is melted
ICE:
Q_1 = cm(T_i - T_f)
Q_2 = Lm
for the ice the total heat Q_1 + Q_2
WATER:
Q = cm(T_i - T_f)
the final equation looks like
Q_1 + Q_2 = Q
then using the correct values of c,m...
i have an easy problem that i can't solve
if you throuth 100g of ice at a tempeture of -15C in a glass with 200g of water at a tempeture of 25C.
what it the final tempeture of the system? the system is isolated, no heap can get in neither get out.
i try to solve this problem using...