Recent content by Martin Jediny

Thank you, I think you have found my lost energy.

can you give me some advice, please? What is the process? (I've always solved the adiabatic plot with gas/steam only.) Column 2-3 is full of water and is ideally insulated. The column does not trap heat, nor does it accept heat from the surroundings. If the volume of water increases slightly...

From the start it is 2 columns, one cold and one hot, ideally thermally insulated. T2=T3 and T4=T1 this process of 2-3 and 4-1 is therefore isothermal The columns are top and bottom connected. (Consider the free natural circulation of water, using the different densities of hot and cold water...

I apologize for reindexing the variables, but they make better logic for the p-V diagram. 1kg/s flow rate Line 1-2 lower pipeline, pressure 10MPa. Heating P12= 20.93 kW ? +36W ? Point 1: 90°C, Ro1=0.96978 g/ml, Enthalpy: 384.73 kJ/kg , Cp=4.1837 J/(g.K) Point 2: 95°C, Ro2=0,96641 g/ml...

Thank you for the recommended tables and patience If I'm quoting correctly, it's 90/95 for the fallout at pressure 0,1MPa I need 21,04 kJ to heat 1kg of water (just a note Cp=4,2102, dRo= 0,96531-0,96189=0,00342 g/ml) and at a pressure of 10MPa I need 20.93 kJ for 1kg of water (just a note...

sorry, maybe I found my problem. Please, how much heat do I need to heat 1 kg of water from 90°C to 95°C, at constant pressure? Please be accurate to 4 or 5 significant digits if it is possible At a pressure of 1 bar At a pressure of 100 bar

I don't know if I understand you all. I would like to be clear. If I have a simple circuit without turbines. Flow rate 1kg/s a height of 1km with perfect thermal insulation. And one column with water has a temperature of 90°C and the other has a temperature of 95°C, How much power do I need down...

I guess I didn't understand what you wanted from me in the previous posts. Yes, that was the first idea that heating and cooling are the same. Through enthalpy, it is 21.06 kJ / kg. Then I heat and cool 21.06 kW. But if I have the same heating and cooling, then we will have to find another...

I apologize if I caused confusion with an imprecise definition. In any case, I want to use a real liquid and not water in the end result. but I don't want to complicate it now. the only problem is that the required transmission height is many times higher than for other liquids. But this is not...

Let's create a random example. Let's say we have a continuous continuous flow of 1kg/s (Q=0.00104 m3/s (hot side)) of water in our plant. The cold water down entering the heater will have a temperature of 90°C. The water coming out of the heater will have a temperature of 95°C. The density of...

Heat_capacity_of_water_2.jpg

I don't know if wiki is a good source, but it says that I need 4215 J / K / kg for cooling, while for heating I need 4165 J / K / kg , just for hydrostatic pressure for example 200bar. (https://en.wikipedia.org/wiki/Heat_capacity, April, 2024) And flow is the same.

Thank you for giving me your time. I don't have any temperature in the formula at the turbine. Turbine power: P1 = dp * Qv * ni dp pressure difference inlet/outlet Qv Flow rate (m3/s) ni efficiency dp = h1 * dRo *g h1 hydrostatic head dRo density difference between hot and cold column g 9,81...

I know the steam cycle very well and can design steam turbines with superheated steam and regenerative cycle. (apologies for the propeller) I'm really interested in incompressible fluid now and I'm not going to revolutionize the energy industry. An incompressible liquid is really unsuitable for...

Ok thank you. Please, can you help me, how much does the temperature of the water drop when it passes through the turbine?