Have you been taught all of the basic kinematic equations?
If so, look at each of them. You'll find that each one has a different variable missing.
Knowing this all you have to do is look for the equation with all the variables you're given and the variable you need and then use that.
Okay. You understand that, as a vector quantity, displacement is a number value representing distance combined with an angle, measured from a certain point. This problem takes away the need for an angle, because the car can only move in two directions - forward and backward. This makes it easy...
What exactly doesn't make sense?
Do you understand what the product of a velocity-time actually is graph is?
Are you aware of the vector nature of velocity and displacement?
Give it a crack first. Write up your attempt here :) It's against the rules of the forum to give help without the asker proving they're not just being a slacker.
Power is given by P = VI.
V, voltage, is energy per charge (Joules per coulomb)
I, current, is charge per time (Coulombs per second)
From this we can see that if we increase the voltage, the overall energy output will increase.
We can also see that if we increase the current, the same will...
Ratch, your addressing questions to which I already know the answer. What I wanted to know was the voltage across the transistor when the LDR as at the resistances given, and why it is so. I now know that because the transistor is off 10V of potential is stored in the wire, and that 10V of...
So basically, given the tiny current that comes about as a result of the massive resistance of the transistor, and given the tiny voltage drop across Rc that comes with this current, I can essentially look at that path through Rc to Vout as an extension of the cell.
Well static friction is the frictional force between the mass and the plane when the mass is stationary. For example if I had a 10kg mass and a Us of 0.1, the frictional force would be mg0.1. We'll take that to equal 10N because I'm feeling lazy and 9.81 is just too much.
So the frictional...
Yes, however don't expect any help from me on that one. I could sit down for a while and try it but I'm by no means a physics guru like some of the people here. While you can apply the same principles, there's a few other principles you need to apply. Like force to overcome static friction etc...
Yes. Given that potential is lost, however small an amount, across Rc, current would have to flow through it. This current cannot then flow through the transistor to lose its potential at earth..
(I now see what you're getting at. Okay, The current is actually very small.)
But still, there is...