Recent content by Maru

There is a reason why you are given the values f(1) = 3, f'(1) = -2, f''(1) = 2, and f'''(1) = 4. This is because you are expected to simply plug them in, along with each constant c, which is just the point you are "expanding about," in this case, 1. Seems simple enough huh? Thus, you plug the...

I would say learn MATLAB. MATLAB is used heavily in Physics research at my university. In fact, our Computational Physics course is all MATLAB. That being said, C is equally important. Much of the MATLAB programming is done in MATLAB but in C the language due to the control the programmer has...

Hi Learnphysics, You have done the transformation correctly. Since R3 is dangling, it is not part of the Thevenin equivalent resistance, and so you ignore it. No current is flowing through it since it is an open, so it cannot contribute to the equivalent resistance. So You'll just have: Zth =...

Sorry, I edited my post. Reread what I had done. If you do what I said for Node 2 you will get the right answer: Voltage at Node 2 = (I3-I4)R5 = (0.396691mA--0.08609047mA)*10000 = 4.83V A bit off, perhaps a rounding error, but I believe this is correct. Just remember, when you are trying to...

Don't let the schematic confuse you. It might help to redraw the circuit as below. Redrawing in this manner does not affect the nodes, since the voltage is the same across a wire. I assume that the four mesh currents you found are from redrawing as I did below. The voltage at Node 2 is the...

Yes. The question of linearity requires that a system must be closed under addition, scalar multiplication, and contain zero to be considered linear. A linear differential equation and a linear system are linear under these same qualities. In fact, linear differential equations can create a...

A discriminator is an electronic circuit that has an output voltage only when the amplitude of the input pulses exceeds a predetermined value. In the context of light detection, I'd say that if they are using a photodiode as well, they could be attempting to activate a circuit element if the...

Semiconductors...a notorious class where I'm from