Recent content by mathgirl2007

okay i did that. now where in there can i find what c is?

im really stuck. would it be that C must b be 1 to tend towards zero?

im not sure how to find that here. is that the derivative in regards to x?

its going to have to be getting infinitely smaller

u(x) = c1e^(-C + the square root(c^2 - 96))/8)x + C2e^(-C - the square root(c^2 - 96))/8

i really don't understand this one. can someone please just explain how to find k for me

and the roots would be (-C+/- the square root(c^2 - 96))/8

So the equation would be 4\lambda^2+C\lambda+6=0

this is all i was given. would it be that m=4 lambda=c and k=6?

Find the value of the constant c so that solutions of the equation 4u"+cu'+6u=0 tend to zero as fast as possible. I think that c must be positive in order for this to tend towards zero but I cannot figure out what c has to be. Thanks for your help!

A 20-kg mass was initially at rest, attached to the end of a vertically hanging spring. When given an initial downward velocity of 2 m/s from its equilibrium rest position, the mass was observed to attain a maximum displacement of 0.2m from its equilibrium position. What is the value of the...