Thanks for all your help. Definately helped me sort through the solution.
I ended up implementing the numerical solution (just using the brute force method through all values of theta basically root finding). But it's nice to know that I wasn't completely off base with my assertion that there...
Indeed it is. I probably should have not skipped so many steps in the orignal post... v_f = \sqrt{v_0^2 - 2gy_f}
Thanks for the replies. Still processing your later posts...
EDIT... What I said above didn't make much since... there was no theta... so you have something here... looking into...
I believe this is what I did in the attachment. Is it not? Yet, I only got one value... Not sure what I am missing.
Sorry it isn't in TEX. I did it in OpenOffice.org which is almost not completely TEX-like.
I was told by a professor that there was no analytic solution (it's a numerical methods course) when there is a elevated target. However, I can't find anything wrong with the analytic solution I came up with. Would anyone mind confirming that my formula (attached gif) for the launch angle when...