Recent content by Matt Howard

Yes, I am sorted now, thank you very much! I have now completed the work, thanks again!

That is correct, the switch is being moved from the lower position to the upper position at t=0

So simplified is 7=14-14e-t/1.7x10-3 The only idea I could find (Until Svein commented) was working it out from the fact that the capacitor is 63% charged when 1 time constant had lapsed. I worked out the voltage from that and thought I could work out the time from the differences in percentage...

I think I vaguely remember that from class. so for me it would be something like: 7=14(1-e-t/1.7x10-3)? Is that right? I'm assuming it's t I'm looking for so how would I go about transposing that to solve for t?

I'm unsure of the best way to go about finding out the time it takes for the capacitor to reach a voltage of 50% of V1. V1: 14V Resistor before 2pt switch: 1K ohm Resistor after 2pt switch: 220 ohm Capacitor: 1.4 micro farads (Charging) 1 time constant is 1.7mS (Discharging) 1 time constant is...