Recent content by Matt4936

That means that you would have to integrate the acceleration function to get the velocity function and then substitute time in?

For the first question you would multiply the acceleration by the time. For the second question you would get the velocity and multiply that by the time. Also acceleration is ms^-2 not -1. I'm sure that was just a typo but I'm just making sure.

For the first question you would multiply the acceleration by the time. For the second question you would get the velocity and multiply that by the time. Also acceleration is ms^-2 not -1. I'm sure that was just a typo but I'm just making sure.

Sorry, I misinterpreted the whole question. The train derails and 'fuses' with the car and I find the momentum and then I find the north component's momentum and then find v from there. As for how I got 36.75m/s; I mustn't have been thinking properly because I multiplied the distance by the...

36.75m/s

F(net)=F(applied)-F(friction) D= distance the box moved after acceleration

You find the force acting against the box and take that away from the force required to accelerate the box to get the net force.

Since I am able to find the initial velocity the moment after the collision; is the velocity of the car before the collision equal to the north component? I get approximately 34m/s.

Yes, the train and car are traveling at right angles before the collision and the car does bounce off the front of the train and we also do assume that no velocity is lost during the collision. SorryI didn't add this information, I just subconsciously assumed this after looking at the...

Homework Statement A train which weighs 1.4406E4N hit a car with a mass of1470kg. The cars skids 15m at angle of 68° to the crossing and the coefficient of friction between the tyres and the road is 0.25. Find the initial velocity of the car entering the crossing. Homework Equations...