Recent content by May11

I will bear that in mind !

Mv²/2 is undoubtedly positive. 1-M/m+M: 1>M/m+M M+m>M<1 = positive. Umm, makes sense. The teacher said we have to use more formulas which are not given in the question, haven't expressed them, to branch out a little from what we are given. I will ask if your proof is valid and acceptable...

V1 (velocity of M before the collision) = v V2 ( velocity of m before the collision) = 0

Two masses, actually.

It is a plastic collision, masses exert forces on each other, ending up with a joint velocity (U). We fisrt have to express the equation of the velocity at the end of the collision, that is : U= Mv/M+m Then, express the equation of Ek0 and Ek1 : Ek0= Mv²/2 Ek1= (m+M)u²/2 = M²v²/2(m+M) Then...

Did you get my question? need a further explanation?

Ek0 is the initial kinetic energy that an object possesses. Ek1 is the eventual kinetic energy that an object possesses. Try to prove that Ek0-Ek1 (energy loss) equals a positive value.

Hi there, I need your help to prove the following, please: Ek0-Ek1>0 Thanks in advance. (: