thanx a million i know see were i went wrong yup its equal to 1.23 sec
for b i used dx=(Vx)(t)
Vx=5.0 m/s x Cos35=4.09m/s
dx=(4.09m/s)(1.23s)
dx= 5.03m
for c i did V^2=(5.0m/s)^2+2g(4m)
V= 10.16 m/s
i just can't figure out how to get the angle,i know I am supposed to use the tan...
Gneill when i use the quadratic form, and plug in the given variables i do not get 1.27 or 1.23 or anywhere near that
∆t = -2.86+/- sqrt -2.86^2-4(4.906)(-4)/2(4.906)
t=-3.8 or -1.91