am i right in saying this:
if the ice block is fully submerged, the Volume displaced will equal the volume of the ice block.
if the ice block is somewhat submerged, the volume displced will be less than the volume of the ice block
Sorry, I meant pressure will vary, not density.
Ok if the ice block will displace it's own mass (100g) in a solution, it will displace 100ml if the densities were the same? As the density of the fluid is 1100kg m-3, whereas the iceblock is 900kg m-3, it won't be 100ml displaced.
As named...
Regarding pressure - depth standpoint: i understand that density will increase as the object decreases vertically. no change horizontally at a fixed depth.
thanks for your help.
Ok I am very new to physics (3 weeks) so i don't know or understand what calculations will keep this straight forward; as i still don't have a formula to work with.
nonetheless i'll try and workout what you mean:
- ice is .1kg
- how much solution needs to be disaplced to keep forces...
I'm not really sure. I'll guess that it would almost be fully submerged; and as the ice block weighs less than the fluid it would float. By how much I don't know.
Yes I didn't look at that calculation like that. It isn't ^3, only ^2.
1.5*10^-7Q1 = 1*10^-15 - 5*10^-8Q1
Q1 = 6.67*10^-9
2*10^-15 - 1*10^-7Q2 = 5*10^-8Q2
Q2 = 1.33*10^-8
I am honestly as lost as when I started as I don't have a definitive approach in why certain variables are, or aren't related.
Thanks for your help and persistence.
Unfortunately I don't get an answer near 70% which is the correct answer. I think i must admit defeat, considering time spent.
Thanks again :)
doesn't V need to be solved for? substituting q1 into the last equation and solving for q2 will equal 0.
so to clarify:
c1 = 0.05uF
c2 = 0.1uF
q1 = 2x10^-8
V is unknown
q2 is unknown