so I have a semi circle that goes from
\frac{5\pi}{4} to \frac{\pi}{4}
so the angle between the x-axis the radius of the circle is 45 degrees.
I have, letting the radius = a)
\frac{1}{a} \int \.dl
this is going to have an x and y component, I know the x component is 2a in the...
ok..scratch everything out. I just e-mailed my prof. and he said that we don't need to use delta function and to only use \int \.dl for the path from beginning to end. *dl is a vector
ok, I got most of it, but what is "s" inside the delta function? so we get something like this
\frac{\mu_{0} }{4\pi} \int \frac{I\delta(s-b)\delta(z)\hat{\mathbf{\phi}}}{R} \.d\phi + \frac{\mu_{0} }{4\pi} \int \frac{I\delta(s-a)\delta(z)\hat{\mathbf{\phi}}}{R} \.d\phi...
If you have griffith, look at problem 10.10, page 427, sec. 10.2...it doesn't seem like we have to actually have to worry about the straight pieces. and if we use cylindrycal, then I moves in the phi direction.
It's griffith...what can I say? and he doesn't just equates them both, he somewhat vaguely shows the reason why you can do this. but forgetting that...I'm still stuck as to where to what to do now.
True true. According to the book, J(r', t) =I(t) so I will have the direction of J, and that will make A have the same direction. So, shouldn't the direction just be X in this case?
oops, sorry i didn't notice the plus sign for the definition of the retarded potential. I've been deprived of coffee until now, so now I'm thinking more clearly. the problem states that the wire is neutral, so when calculating V, we don't need to worry about what the charge density Rho is since...
I don't know how to enter formulas so I'm posting an image of the formulas. so, I pretty much need to find phi and A, for the configuration in the previous picture of the wire carrying a uniform current I=ct
thanks for the reply gabba. I uploaded a picture, and I thought I did use the template provided. maybe part c was the one I didnt do.
I haven't plugged anything in, but I was thinking using V1-V2 = int(dl) - int(dl), however, since I only have half of the circle, should my limits of integrate...
there's a wire shaped as a circular loop that carries a current I=ct. half the loop has radius A and at 45 degrees the radius of the second half of the loop changes to b. Find the retarded potentials V(t) and A(t)
The way i thought of approaching this is by dividing the loop into two...