Recent content by Mehta29

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    Circular Motion: Ferris Wheel Dynamics

    i got A and B...but how would i manage part c? im not seein anyway to cancel out the mass...
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    I NEED major help, its about getting time?

    I think people on these boards are more familiar with teh ViVfdat method (same sort of thing...) again same sort of concept as ur last problem...no initial y velocity...no x acceleration...then just set up a system with the values...knowing that acceleration in y direction is g and then...
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    Circular Motion: Ferris Wheel Dynamics

    but I am confused as if anything else would be needed...liek that blank befor e the W...would i need to expand any further or would i just keep it Fnbottom - Fntop = xW b would just be v^2/r = g? and then t = 2pir/v and c would be Fnb = mv^2/r + mg...but how would i eliminate m?
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    Circular Motion: Ferris Wheel Dynamics

    I'm on the right track, but I'm stuck here... The radius of a Ferris wheel is 5 m and it makes one rev in 10 sec a Find the difference b/w the apparent weight of a passenger at the highest and lowest points, expressed as a fraction of his weight, W b What would the time for one rev be...
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    Universal Gravitation and Satelite Motion

    well i got part a...instead of a quadratic i just took the root of everything...now part b seems to be confusing me...g = GMe/R^2?
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    Universal Gravitation and Satelite Motion

    hmm I am still gettin two #'s that don't make sense for the first one... okay so acc = acc v^2/r = GM/4r^2<<?
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    Universal Gravitation and Satelite Motion

    for the first one i got 431305921.4 m/ 337924847.8 m arent those both between the Earth and the moon? i don't get which one would be the correct answer in this case... and for the 2nd question...would it be m^2 because u have would have the masses of each being equal? so v^2/r =...
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    Universal Gravitation and Satelite Motion

    Algebraically I got R^2 - 2Rx + x^2 = Mm/Me x^2 is this correct? but I am getting two positive values for the quadratic? and for the 2nd one... v^2/r = G2M/ R^2 ? where R is 2r?
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    Universal Gravitation and Satelite Motion

    A couple of questions that I am struggling with again...that I really need to figure out ASAP On the way to the Moon the Apollo astronauts reached a point where the Moon's gravitational pull became stronger than the Earth's. (a) Determine the distance of this point from the center of the...
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    Determining Acceleration for Block A to Avoid Falling from Cart

    okay i understand the acceleration part...a = g/μ...was just a little confused because the normal force had no force acting in the opposite direction...but how would it look to an observer? wouldn't it just remain stationary and look like it was a part of the cart?
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    Determining Acceleration for Block A to Avoid Falling from Cart

    Umm...I having trouble with the concept of acceleration and friction i guess...or something... What acceleration must a cart have in order that the block A will not fall the coefficient of static friction between the block and the cart is μ , how would the behavior of the blokc be described...
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    Kinematics Questions: Solving for Superman's Velocity and Building Height

    I understand the majority of introductory kinematics...except for these couple of questions... Question #1 A student falls from a 300 M building and starts free fall, five seconds later, superman arrives and dives off the roof to save the student... a) what must be superman's initial...
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    Questions on Electrostatics/Electricity/Stuff?

    thank you very much, electrostatics really isn't my strong suit...meaning there will probably more to come soon...
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    Questions on Electrostatics/Electricity/Stuff?

    okay i just found this forum and i think now would be a good time to utilize it... okay first q... 1) Two lightbulbs, one rated 30 W at 120 V and another rated 40 W at 120 V, are arranged in two different circuits, if connected in series to a 120 V source, what is the resistance and...
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    Magnetic Fields and Maximum Current

    well i found the error of my ways... the whole +/- 1% threw me off... i get the right answer if i multiply by the magnetic field by 1% and then re-plug everything in... hopefully this helps someone in the future...
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