Recent content by Melssssss

well you can solve for T from the first equation since you know the mass and gravity. then plug it into the 2nd equation.

sorry t cos(theta)

Tsin(theta)= electric force?

electric force is pulling to the right and tension is also pulling to the left slightly but I am unsure how I would make that an equation

Tsin 30= mg

the forces would be tension, weight of the ball and electric force. so since the ball is at equilibrium the net forces are equal. so if tension is pulling up and gravity down, tension is also pulling left and the electric force right. so if I find the tension would this be equal to the electric...

This is the picture provided.

by using the equation I gave, which only uses the area and charge,

yes but how is the mass and the angle come into play?

are you talking about the capacitance? That's the next chapter and isn't related to this problem

in this case, 4.1128. so then I would plug all this into this equation x= vf2-vo2/2a?

ta + v(initial)

but the velocity is changing, the picture of it wouldn't load.

Homework Statement A particle of charge +14.5http://edugen.wileyplus.com/edugen/courses/crs6407/art/qb/qu/c18/lower_mu.gifC and mass 5.09 × 10-5 kg is released from rest in a region where there is a constant electric field of +328 N/C. What is the displacement of the particle after a time of...