Dear BTown and xxChrisxx
I've been working on a document (with your help) that I've uploaded to a blog called process arts (a project run by the university of the arts London) my employer.
The document is a toe dip for me into creative commons licensing in that I want to encourage readers...
Hi xxChrisxx
This makes perfect sense. Does it follow that if the tube (beam) is supported at both ends, that the maximum distance would be twice that of the canterlevered calc?
I'm back
but this time I'm trying to understand more fully the equation.
If below is correct what is the term given to 'half the thickness of the tube? is it youngs modulus?
Yield strength = (moment of turning force) x (half the thickness of the tube ÷second moment of inertia)
You make it look so easy. I wonder why the online calculator didn't work? I was looking for an idiot proof way of solving the equation and got an idiotic answer.
I think my basic maths is missing, I've never had much success with quadratic equations. I won't pester you any more, better I go...
Okay bear with me, the cogs are whirring
right I've pumped all of these figures into an online calculator and have got the staggering answer of x=1726649842565500
that seems like a pretty big number to me can you help me make more sense of it?
I've got my figures together and wondered if you would be so kind as to check this equation, then hopefully help me work through solving it?
250N/mm2 (steel yeild strength) = (70kg * x)*(12.5mm /1.56cm4 (second moment area as stated in tube specs)
Do I have to convert the 1.56cm4 (second...
Dear BTown
I can't believe it I really think I understand what you're talking about, you kept the two parts apart and left x unknown in the equation!
Now I need to read your post again and do some more thinking.
Off home now but will post again soon
Slowly a light is glimmering at...
Okay so here's my first stumbling block.
How can I find the 'moment' if I do not know the distance the the person will be standing at yet. Am I missing something?
Okay BTown
a bit scary I wish this language were a familiar to me as to you guys. But I'm not a lost cause, I will try to employ these formula, it will give me a mathmatical pedestal to stand on a survey lesser mortals (currently me)
Thanks xxChrisxx
I'll give it a try and post my progress if that's okay?
Got to go and help a student make a giant sewing needle, no physics there I can't handle.
All the best
It may sound like a silly question but I really need some help. Not with the maths, I know that's beyond me I'll plug the numbers into an online calculator when I know what it is is I should be doing and that's where I need you.
The set up:
A random length of 25mm square tube with a wall...