Hey Chiro,
I'm not completely sure what you mean.
I have the following formula:
ƩXi ~ N(nμ, nδ2).
Should I use that to sum of the 20 wines? (n = 20, μ and δ given)
I'm unsure how to use this together with the normal distrubition for the volume of the cask.
Hello all,
While studying for exam I came across this practise problem which is giving me some trouble.
The amount , A, of wine in a bottle ~ N(1.05L, .0004L2).
a)The bottle is labelled as containing 1L. What is the probability a bottle contains less than 1L?
b) Casks are available...
I think this is what you mean:
P(x<a) = F(a).
I used that to get F(-a) = 1- F(a).
So for P(-a<x<a) I thought it would be F(a) - (1 - F(a)) = 2F(a) - 1 = 0.95 ?
Was I doing it correct?
Hi all,
I was having some troubles with a practise question and thought I'd ask here.
Given an r.v. X has a pdf of f(x) = k(1-x2), where -1<x<1, I found k to be 3/4.
And I found the c.d.f F(x) = 3/4 * (x - x3/3 + 2/3)
Now I have to find a value a such that P(-a <= X <= a) = 0.95.
I thought...