Recent content by MIBinRN

a) R = kv Summation F = F-R = F - kv By Newton's Second Law of F=ma, F - kv = ma F = ma+kv = m(dv/dt) + kv Thus, P=FV. b) ODE = P=FV =(m(dv/dt) + kv)(v) =mv(dv/dt)kv^2 c)V = Vmax when a=0 Thus summation F= 0 F-kv=0 F=kv d) Given P = 80000Watts, V =...

Ah... Okay. Sorry. Thanks. Is there a place I can go to ask such questions? And I'm not sure how to continue as I'm already lost from the beginning cause I don't know what is the concept behind it. In any case, I apologize for my tardiness.

Could anyone help me solve this problem? It has been mind-boggling for me cause I have only started to venture into this topic.

A car of mass 1200 kg is started from rest and pulled on the level ground by an engine. The resistance of the motion is Kv, where v(m/s) is the velocity of the car at time t(s). The power of the engine is constant and equal to 80000 watts. a) How does P, the power of the engine connect to F...