Recent content by Michele Nunes

I finally got it, I've been working on this problem for so long. Thank you so much!

The derivatives have to be equal at P and Q, right? So I set the derivatives equal, but I need another equation in order to solve for both variables. Is there something I can do with the original equations? I can't set them equal though because the points don't happen at the same y-value.

I'm sorry but I still don't understand how that relates to what I'm supposed to do. They're supposed to have only one solution to what? If I set ax+b equal to the quadratic equations, there's still too many variables for me to solve for which is where I'm confused.

Homework Statement Sketch the graphs of y=x2 and y= -x2+6x-5, and sketch the two lines that are tangent to both graphs. Find equations of these lines. Homework EquationsThe Attempt at a Solution So I know that a tangent line to both graphs means that the tangent line will touch the first graph...

Homework Statement Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the y-axis. y = 4 - x2 y = 0 Homework EquationsThe Attempt at a Solution Okay I understand that the region is symmetric about the y-axis...

Yes for the most part, thank you!

Yes, but I would have 123456788/(222 * 104) + 1/(222 * 104) and if I ONLY divided 123456788 by 104, then where did the 222 in the denominator go and if I ONLY divided 1 by 222, then where did the 104 in the denominator go, do you see what I mean?

Okay I'm kind of making sense out of it. If you divide 1 by 222 then you will have 22 decimals, and then if you divide 123456788 by 104 then you will have 4 decimals, and 22 + 4 = 26, I don't know though something about that process seems off, I feel like you can't just separate them like that...

Homework Statement What is the minimum number of digits to the right of the decimal point needed to express the fraction as a decimal? a) 4 b) 22 c) 26 d) 30 e) 104 Homework EquationsThe Attempt at a Solution One possible solution is: "We can rewrite the fraction as . Since the last digit of...

Oh okay I understand where the fractions came from now. But why exactly do you multiply them?

There are 6 equally likely possibilities and Carol can pick any 1 out of the 4 non-yellow marbles, so 4/6

Homework Statement A box contains 2 red marbles, 2 green marbles, and 2 yellow marbles. Carol takes 2 marbles from the box at random; then Claudia takes 2 of the remaining marbles at random; and then Cheryl takes the last 2 marbles. What is the probability that Cheryl gets 2 marbles of the same...

Ohhh I see now. I did chain rule on the wrong term. That's why it was coming out funky. Thank you!

Here's how I did the second derivative: I'm taking the derivative of (3x2)*(g(x3)), and I'm going to let (3x2) = u and (g(x3)) = v so the second derivative should look like: d2/dx2(f(x3)) = u'v + uv' My first term came out nice: u'v = 6x*g(x3) Now for my second term, I said that v' = f(x6)*6x5...

Homework Statement If d/dx(f(x)) = g(x) and d/dx(g(x)) = f(x2), then d2/dx2(f(x3)) = a) f(x6) b) g(x3) c) 3x2*g(x3) d) 9x4*f(x6) + 6x*g(x3) e) f(x6) + g(x3) Homework EquationsThe Attempt at a Solution The answer is D. Since d/dx(f(x)) = g(x), I said that d/dx(f(x3)) should equal 3x2*g(x3), then...