# Rotational Volume Using Shell Method

• Michele Nunes
In summary, the conversation discusses using the shell method to find the volume of a solid generated by revolving a plane region around the y-axis, with equations y = 4 - x2 and y = 0. The individual is confused about why the integral 2π∫[from -2 to 2] (4x-x3)dx yields 0 when plugged into a calculator, and questions whether rotating the region from 0 to 2 and -2 to 2 would give the same result. The expert explains that the wrong answer is obtained because the shell method was applied incorrectly, and suggests using a = 0 as the lower limit of integration.

## Homework Statement

Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the y-axis.
y = 4 - x2
y = 0

## The Attempt at a Solution

Okay I understand that the region is symmetric about the y-axis, however I still don't understand why the integral 2π∫[from -2 to 2] (4x-x3)dx comes out to be 0 when I plug it into my calculator. I know that you can just do the integral from 0 to 2 and then multiply the whole thing by 2 and it comes out correctly but why does doing it from -2 to 2 come out as 0? Aren't both methods trying to calculate the same thing? Why do both get different answers? Wouldn't rotating just the region from 0 to 2 about the y-axis and rotating the region from -2 to 2 about the y-axis give you the same cylindrical solid?

Michele Nunes said:

## Homework Statement

Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the y-axis.
y = 4 - x2
y = 0

## The Attempt at a Solution

Okay I understand that the region is symmetric about the y-axis, however I still don't understand why the integral 2π∫[from -2 to 2] (4x-x3)dx comes out to be 0 when I plug it into my calculator. I know that you can just do the integral from 0 to 2 and then multiply the whole thing by 2 and it comes out correctly but why does doing it from -2 to 2 come out as 0? Aren't both methods trying to calculate the same thing? Why do both get different answers? Wouldn't rotating just the region from 0 to 2 about the y-axis and rotating the region from -2 to 2 about the y-axis give you the same cylindrical solid?
You get the wrong answer for the volume using

$$V=\int_{-2}^2(4-x^2) ⋅ xdx$$

because you have applied the shell method incorrectly. Since the region y = 4x - x2 is symmetrical about the axis of rotation, in this case the y-axis, you should have made the lower limit of integration a = 0 instead of a = -2.

http://tutorial.math.lamar.edu/Classes/CalcI/VolumeWithCylinder.aspx