Rotational Volume Using Shell Method

Click For Summary
SUMMARY

The discussion centers on using the shell method to calculate the volume of a solid generated by revolving the region defined by the equations y = 4 - x² and y = 0 around the y-axis. The integral 2π∫[from -2 to 2] (4x - x³)dx yields 0 due to the symmetry of the function, which results in equal positive and negative areas that cancel each other out. The correct approach is to evaluate the integral from 0 to 2 and then multiply the result by 2 to obtain the accurate volume. This highlights the importance of correctly setting the limits of integration when applying the shell method.

PREREQUISITES
  • Understanding of the shell method for volume calculation
  • Familiarity with definite integrals
  • Knowledge of symmetry in functions
  • Basic calculus concepts, specifically integration techniques
NEXT STEPS
  • Study the shell method in detail, focusing on its application in volume calculations
  • Learn about the properties of definite integrals and their implications in volume problems
  • Explore the concept of symmetry in mathematical functions and its effects on integration
  • Practice evaluating integrals with different limits to solidify understanding of volume calculations
USEFUL FOR

Students studying calculus, particularly those focusing on volume calculations using the shell method, as well as educators seeking to clarify common misconceptions in integral calculus.

Michele Nunes
Messages
42
Reaction score
2

Homework Statement


Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the y-axis.
y = 4 - x2
y = 0

Homework Equations

The Attempt at a Solution


Okay I understand that the region is symmetric about the y-axis, however I still don't understand why the integral 2π∫[from -2 to 2] (4x-x3)dx comes out to be 0 when I plug it into my calculator. I know that you can just do the integral from 0 to 2 and then multiply the whole thing by 2 and it comes out correctly but why does doing it from -2 to 2 come out as 0? Aren't both methods trying to calculate the same thing? Why do both get different answers? Wouldn't rotating just the region from 0 to 2 about the y-axis and rotating the region from -2 to 2 about the y-axis give you the same cylindrical solid?
 
Physics news on Phys.org
Michele Nunes said:

Homework Statement


Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the y-axis.
y = 4 - x2
y = 0

Homework Equations

The Attempt at a Solution


Okay I understand that the region is symmetric about the y-axis, however I still don't understand why the integral 2π∫[from -2 to 2] (4x-x3)dx comes out to be 0 when I plug it into my calculator. I know that you can just do the integral from 0 to 2 and then multiply the whole thing by 2 and it comes out correctly but why does doing it from -2 to 2 come out as 0? Aren't both methods trying to calculate the same thing? Why do both get different answers? Wouldn't rotating just the region from 0 to 2 about the y-axis and rotating the region from -2 to 2 about the y-axis give you the same cylindrical solid?
You get the wrong answer for the volume using

$$V=\int_{-2}^2(4-x^2) ⋅ xdx$$

because you have applied the shell method incorrectly. Since the region y = 4x - x2 is symmetrical about the axis of rotation, in this case the y-axis, you should have made the lower limit of integration a = 0 instead of a = -2.

http://tutorial.math.lamar.edu/Classes/CalcI/VolumeWithCylinder.aspx
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
Replies
4
Views
1K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K