f=875000000
c=300000000
using ((4*pi*d*f)/c)^2=FSPL
((4*3.14*1100*875000000)/300000000)^2=FSPL
10log(FSPL)= losses in dB = 92.1dB
assuming 0.1dB attenuation per each antenna
Received Power (dBm) = Transmitted Power (dBm) + Gains (dB) − Losses (dB)
Pr=30dbm + 0 - 92.1dB - 0.2dB...
Homework Statement
A signal needs to be transmitted over 1.1km, with 12Hkz bandwidth on FM carrier.
Carrier freq=875MHz.
Allowed up to 1W carrier power transmitted and received thru omnidirectional antennas.
antennas low loss, max attenuation = 0.1dB
Homework Equations
Received...
Homework Statement
calculate the frequency deviation using an approximate technique
Homework Equations
input analogue signal is 1.2kHz
min bandwidth to avoid over-sampling is 3.6kHz
signal transmitted over 1.1km with a 12kHz bandwidth on a FM carrier
Carrier freq is in the GSM reverse...
OK this is the system
1200Hz analogue signal encoded using 8 level PCM
This spec results in a bit rate of 6600 bit/s
Signal transmitted over 1100m, 1200Hz bandwidth, FM carrier.
Carrier freq is 875000000Hz.
Allowed 1W carrier Pt and Pr.
antennas - omnidirectional.
antenna...
With regards to cellular radio systems1. how many bits of information does each cycle of a sinewave carry on a minimum channel?
modulator characteristics
2. A system has narrowband fm characteristics.. name me a rule which is an approximate technique to find the necessary freqeuncy deviation...