Recent content by might hire

Wow, I see that now, the problem is unsolvable, thanks Mike, you saved me a lot of writing! lol

Okay, here is the problem, ; Remesh likes to run outdoors and ride his bicycle at the veledrome. He burns about 400 calories/h running, and 300/h riding his bike. It costs $6/h to ride in the veledrome. Ramesh hopes to develope a weekly exersise program that will burn 4800 calories, cost no more...

Okay, here is the problem, ; Remesh likes to run outdoors and ride his bicycle at the veledrome. He burns about 400 calories/h running, and 300/h riding his bike. It costs $6/h to ride in the veledrome. Ramesh hopes to develope a weekly exersise program that will burn 4800 calories, cost no...

I'll pass the favor on tommorow:) Keep the chain going.

lmao, you sure have:D

The final answer is (3,7)

Oh man, jeeze, I can't believe I forgot that, thanks so much! :) You've both helped a heck of a lot!

We were taught substitution.

yah, 100x+60y=880, sorry about that.

The bastow family drove to visit relatives. They drove a total of 880km in 10 hours. Their average speed was 100km on highways and 60km in the city. Let the time traveling on highways be "x" hours and the time on city roads be "y" hours. An equation that represents the total difference...

By the way, I have to find the hours in which they drove on each road type.

I have a question, a huge one but simply it is.. A family goes on a ten hour drive, 100km an hour on highways(x) and 60km(y) an hour on city roads. 100x+60y+880, and x+y=10 Just need a push in the right direction. Thanks in advance.