Recent content by mihalisla

Hello! I ve come across with something called ' relative element of a vector' Could you provide me a definition and how is it used? Thank you

Solved Solved ! lamda=x*x' and the corresponding eigenvector is x

How can I define the rank of that matrix that is always one ? Then I can get on from this forum from https://www.physicsforums.com/showthread.php?t=682216

Sorry but i still don't get it. What is the eigenvector in the second part of the equation? Could you provide the solution beyond that first step! Thank you !

I tried it but i get a nx1 in size matrix. Aren't eigenvalues and eigenvectors for nxn matrices . . . ? How can I get the values ? Thank you .

I ll try it . thank you very much!

Hey guys if i have a vector x=[x1,x2, ... xn] what are the eigenvectors and eigenvalues of X^T*X ? I know that i get a n by n symmetric matrix with it's diagonal entries in the form of Ʃ xii^2 for i=1,2,3,. . . ,n Thank you in advance once again!

I have one more but i ll post it in new thread ! P.S I m new here so posting the solution is good , isn't it ?

Solved Problem solved ! Matrix A=[a ,b] [b, d] From A*H.1=lamda1*H.1 I took lamda1=(a*sin(x)+b*cos(x))/sin(x) and lamda1=(b*sin(x)+d*cos)/cos(x) From A*H.2=lamda2*H.2 I took lamda2=(a*cos(x)-b*sin(x))/cos(x) and lamda2=(d*sin(x)-b*cos(x))/sin(x) For each set of...

I started from the eq A*H.1= lamda1*H.1 where H.1 is the first column of H (the A matrix of user HallsofIvy) . Then I did the same for lamda2 (the second eigen value that is unknown) and I got lamda1=]a*sin(x)+b*cos(x)]/sin(x) and another value lamda1=[b*sin(x)+d*cos(x)]/cos(x). Also two...

no there are not fixed eigen values! how do I proceed?

I have made the assumption that matrix A should be symmetric because of the orthogonality of eigen vectors matrix! is this true? so matrix A = (a,b ;b, d) rows separated by ;

^T is the transpose? and why [1,0]? thanks!

Hello to all of you, Is there a way to get the matrix A=[a b c d] from the eigenvectors (orthogonal) matrix H= sin(x) cos(x) cos(x) -sin(x) or to pose it differently to find a matrix that has these 2 eigenvectors ? Thank you in advance . Michael