Recent content by mike3

The model stove puts out 50,000 BTU/hr with a 10" diameter fuel chamber and it takes one hour to burn out 6lbs of fuel, using a 240mA electric power to a small fan. I want 116,000BTU/hr. My guess is: 116,000 / 50,000 = 2.32 Which means the new stove needs to produce as much heat as 2.32...

Yes, I'm certain the dimensions are controlling the rate of burn. Now it's trying to figure out the right dimensions to create the right amount of heat output over time and keeping the heat in production for 6 hours minimum. So, how do we calculate the radiant heat output? and how can we...

Yes, I agree, and the rate of burn for the wood gas is controlled by the fan. And, I guess fuel type (which has it's own BTU/hr). The numbers provided by these stove makers suggest a burn rate of 6lbs of fuel/hr @ 50,000 BTU/hr. Now, it's a little strange that they have these figures without...

The greenhouse has 2 propane heaters in it right now on either end of the same type. They are both 75000 BTU/hr Input and 60000BTU/hr output. I should have mentioned this earlier. Last year I only used one of them and it was enough to heat the space (though I kept it at 50F during end of...

I am trying to design a heating element to heat a greenhouse. I found a very accurate calculator that helped me find the BTU/hr I need to heat this area to my desired night time max temp, that figure is 116,556.8BTU/hr. I need to figure out the dimensions of the stove I am building so I make it...