Recent content by MikeLowri123

  1. M

    EM algorithm convergence KF log likelihood decrease

    Can anyone offer a small piece of advice or even a reference??
  2. M

    EM algorithm convergence KF log likelihood decrease

    Hi everyone, Im running the KF to learn parameters of a model, the log likelihood of the p(Y_{k}|Y_{k-1}), however decreases. Can anyone advise, does this mean my implementation is wrong or can this just be the case. Advice appreciated Thanks
  3. M

    Why Do Matrix Expressions Often Involve A A^T in Factorization?

    For example when removing the L term from the variance in the attached equations, can you make this out?
  4. M

    Why Do Matrix Expressions Often Involve A A^T in Factorization?

    Hi All, I often see this term when factorizing out a matrix from brackets A(some other term)A^T where I assume A A^T represents the square within the bracket term, can someone explain the reasoning behind expressions of this kind or point me in the correct direction Many thanks
  5. M

    Proving ABC^TA^-1 = CB: Step-by-Step Guide

    14.63 to 14.64, should be an easy substitution but I can't get there
  6. M

    Proving ABC^TA^-1 = CB: Step-by-Step Guide

    I am attempting to work through a derivation and the step attached requires the above mentioned to hold, any suggestions appreciated
  7. M

    Proving ABC^TA^-1 = CB: Step-by-Step Guide

    Thanks for the quick response, Apologies however A and C are symmetric B is not does this chaneg anything
  8. M

    Proving ABC^TA^-1 = CB: Step-by-Step Guide

    Thanks for the reply, on a second look I now have: AB^TC^-1BA=AB^TC^-1CAB^TC^-1 Which I can break down to: AB^TC^-1BA=AB^TAB^TC^-1 is there anyway I can re-order the RHS to equal the left? Thanks in advance
  9. M

    Proving ABC^TA^-1 = CB: Step-by-Step Guide

    Hi all, I have a suspicion this may be obvious but have lookd and can't seem to obtain the correct answer, Can somone please explain the steps required to prove ABC^TA^-1=CB where C^T is the transpose of C and A^-1 the inverse of A. Matrices B and A are covariance matrices and thus...
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