Thankyou Doc Al
That has helped loads. I get the new speed to be 429 RPM which .
If I could ask just one more question just to clarify things. I would just tlike you to explain where the "1" comes from in "KE1/KE2 = 1/0.8". Sorry if its obvious. Is it just how ratios are sorted out?
thanks...
Thanks .
I have ahd a look at the problem again and I am still abit puzzeled.
I get the torque before the [press operation to be 202 Nm and after it has dropped to 162 Nm (the 20% drop).
What I am not too sure about is does the torque in Nm equal the KE?
If it does then i can use KE =...
Hi people.
I wonder if anyone could check a problem I had been set as homework and [possibly point me in the right direction for the second part.
A solid disc flywheel, mass 900kg, 0.75m radius accelerated at 0.8rads/s(sq) from rest to 480 RPM in 63 secs.
a) Calculate the number of...