Recent content by MiniTank

Just wanted to say thanks to everyone on the forums who have responded to my hwk questions when i need help. Now I need a different kind of help on deciding what university to go to. Here is what I am deciding between(Canadian Universities), U of T: Engineering Science, computer option and...

alright thanks ... appreciate it

i think i get what your saying .. Ek = 1/2 |Eg| \frac{1}{2}mv^2 = \frac{1}{2}\frac{GMm}{r} v=\sqrt{\frac{GM}{r}} after i find that .. do i subtract that velocity from the escape velocity of earth?

Earth's escape velocity = 1.12 x 10^4 m/s and the velocity at that altitude is what I am having tourble with

I am having some difficulty with this question: A satellite is in orbit around Earth at an altitude of 3700 km. How much must its speed increase, in km/h, to escape the Earth's force of gravity? I'm stumped. Please help

by cancelling do you mean use the factor theorem? because i would expand and move the 720 to the left side and factor it out

so for b) you get [3(3!)][2(4!2!)] + [2(2!)][2(3!4!] + [4(4!)][2(3!2!)] =5184 Alright thanks

k scratch what i did for (b) i just figured out that's wrong.. assuming what i did in (a) was right, then (b) should be something like 1\bullet2!(1\bullet2!+1\bullet3! +1\bullet1!) =2(9) = 18

any takers?

3 Canadians, 4 Americans, and 2 Mexicans attend a trade conference. a) In how many ways can they be sated in a row if people of the same nationality are to be seated next to each other? b) redo (a) if they sit at a round table for a) the way i look at it is for the Canadians there are...

ahh i see then you get 3!=(5-r)!, then cancel out the factorials and you get 3=5-r.. solve for r .. r=2 .. thanks, that's been bothering me alot i got another question but I am not sure if it has to do with permutations or but it has a similar subject. should i post it in this topic?

how would you solve for r in this situation: P(5, r) = 20 Now I understand you can't use trial and error to find that r=2 but is there any other way using an algebraic technique. Itried something like this.. \frac{5!}{(5-r)!}=20 then \frac{5\times4\times3\times2\times1}{20}=(5-r)...

its not a piecewise function, its continuous throughout. Just to confirm, piece wise means it is discontinuous at certain points, right? i guess my domain was incorrect. I personally wrote out the domain, I wasn't 100% sure if it was right but the graph should be on continuous function...

ya your right. my mistake

i DO know what a derivative is, its i just don't know how to graph the derivative of a function. like in this situation, what i don't get is, would the graph just have a few horizontal lines?