Recent content by minitorpedo

yes, i got it right. Thank you so much! i see that ur quote is from seneca, I am guessing that's Seneca High School in the lenape regional district, becasue I am from lenape. well once again thank u

haha, its ok, so its F_applied = Fspring+Ffriction F spring is what we found, and Ffriction is mgu?

Homework Statement A 30.0 kg block is resting on a flat horizontal table. On top of this block is resting a 15.0 kg block, to which a horizontal spring is attached. The spring constant of the spring is 315 N/m. The coefficient of kinetic friction between the lower block and the table is 0.555...

and doesn't the force from friction need to be factored in too?

im still gettin it wrong using 136

so using this formula of Force_applied = Force_spring, then the mass of the objects has no effect?

An object in motion stays in motion?

wait if the two forces are equal, wouldn't that mean that the blocks won't move at all?

oh oh i thought u meant decimal places. sorry

i can't it only goes to 2 decimal places

and i got part a) correct

i got .432 for the first part, and my k value is 315 so the force should be 136.08 as I am calculating it. i put that in but got it wrong

so the Force_applied = Force_spring and the Force of the spring is -kx and k is 315, and is x the answer to a?

theres the force from the spring which is F = -kx theres the force pushing on the 45kg blocks which is just F.which can't be greater than mgu so the blocks don't slip

the net forces are zero because the blocks are not accelerating