This is what i did:
I first drew a right triangle from the start to the altitude. I got x = 379 m.
I then calculated the x and y components of velocity:
V_ox=87.9cos(59.8)=44.2 m/s
v_oy=87.9sin(59.8)=76 m/s
I know that a_x= 0 m/s^2
a_y = -9.8 m/s^2
v_ymax= 0 m/s
y=652 m
x_max ...
I am really having trouble solving this problem. Can someone help ASAP??
An airplane with a speed of 87.9 m/s is climbing upward at an angle of 59.8 ° with respect to the horizontal. When the plane's altitude is 652 m, the pilot releases a package. (a) Calculate the distance along the ground...