Recent content by Mishi

  1. M

    Stuck on a trigonometry question

    Yes, it was exactly..
  2. M

    Stuck on a trigonometry question

    Exact values for the final answer. I don't know, its my tutors question and answer, sorry if it was misleading.
  3. M

    Stuck on a trigonometry question

    I mean rounded off my bad sorry.
  4. M

    Stuck on a trigonometry question

    Apparently it does tan63°26' = 1.99985903 which equates to 2.
  5. M

    Stuck on a trigonometry question

    No, my question is correct: Show that the exact value of tan31°43' is \frac{\sqrt{5}-1}{2} I got the solution to it. Tan63°26' = 2 tanα = \frac{2tanα}{1-tan^{2}α}= 2 where (where α=31°43' (acute angle)) 2t = 2-2t^{2} t^{2}+t-1=0 , t>0 t= \frac{-1+\sqrt{5}-1}{2\times1} =...
  6. M

    Stuck on a trigonometry question

    woops, sorry typo, tan31° 43' , i think that its possible, but i just forgot how to do it.
  7. M

    Stuck on a trigonometry question

    1. Homework Statement Show that the exact value of tan°43' is \frac{\sqrt{5}-1}{2} 2. Homework Equations 3. The Attempt at a Solution tan2x = \frac{2tanx}{1-tan^{2}x} \frac{2tan31° 43}{1-tan^{2}31° 43'} From here, i got stuck or I'm doing it wrongly, i forgot how to do...
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