I fear I am going to have to slap myself again, but with this corrected equation:
L = \int_1^2 \sqrt{ 36y^6+\frac{1}{576 y^6}+\frac{1}{2}} \, dy
I am still having difficulty despite this advice:
a + b y^3 + \frac{c}{y^3}
What exactly is it that I am missing?
Now I feel retarded. That's what I get for going at coursework for 8 hours straight while tired. I clearly have 576, not 48 written the line above on my scratch paper.
Homework Statement
The length L or the curve given by
\frac{3y^{4}}{2}+\frac{1}{48y^{2}}-5
from y=1 to y=2
Homework Equations
The Attempt at a Solution
Setting up the formula is easy. First I found the derivative of f(y) which is:
f'(y)=6y^{3}-\frac{1}{24y^{3}}
Then I plugged...