Recent content by Mitchel Haas

It's great to see those who put a lot of effort into helping others get recognition! Great job to all!

Yes, this is correct, and you're using the proper reasoning. Be sure to distinguish between v1 and v2

The maximum uniform circular velocity, is limited by the static frictional force of the tires on the pavement. So, Newton's 2nd law gives us $$∑F = f = m a_{\text{rad}}=\frac{m v^2}{R}$$ The maximum friction for available is fmax = usm g. So, you need to consider the radial acceleration...

You'll want to use conservation of energy to solve this, as it's the easiest approach. U1 + K1 + W = U2 + K2. The initial energy is just that of the height of the center of mass (2R), m g h = (.3)(9.8)(2*.2) = 1.176J. The ending energy is the rotational KE of the hoop about the axis, or (.5) I...

There are 9*9*8 = 648 integers which do not have a repeating digit. (1 - 9) * (0 - 9 -1) * (0 - 9 - 2) So, you must pick 649 to insure you have an integer with a repeating digit.