that's true. I don't know why I'm hung up on the negative from the -ΔQh = ΔQc equation. If I don't put the negative there the answer is 58°C, but the answer my teacher gave me in class was 23.4°C. The teacher didn't really show us how to get that answer,. Would you mind helping me with this...
Hi,
Thank you for the fast response.
This is what I had:
Qc = mcΔt + mL + mcΔt = (0.1)(2090)(0-(-40)) + (0.1)(3.33 x 10^5) + (0.1)(4.19)(T-0)
= 41660 + 0.419T
Qh = mL + mcΔt = -[(0.02)(22.6 x 10^5) + ( 0.02)(4186)(T-100)]
= -(83.72T...
Homework Statement
calculate the final temperature when 20 grams of steam at 100°C is added to 100 grams of ice at -40°C.
Homework Equations
Q=mcΔt and Q=ML
The Attempt at a Solution
I tried solving this problem using -ΔQheat = ΔQcold, but the final temperature that I found was past...