ok, so the potential energy of the ball once it get to the top of the tube is mgh, (0.03*9.8*.50) = 0.147J. So The Kinetic energy must equal 0.147 J.
1/2 m v^2 = 0.147 J
1/2 (0.03kg) V^2 = 0.147j
v = 3.1305
Ok that's as far as I can get. Does this means that the minimum velocity must...
I just want to clarify something. This tube is perpendicular with the ground. The ball is basically traveling straight up, just through this curved tube.
Greg
I have attached a diagram of what I am trying to do. This is a side view of a tube that will be carrying that ball up through the curve and back in the opposite direction, just 50 cm higher. The ball is hard plastic and the curved tube is probably going to be hard plastic as well but sprayed w/...