Recent content by mooneh

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    Solving the Kc of a Chemical Reaction with N2O4

    heey i have this chem homework quest : 5 L flask is filled with 0.625 mol of (N2O4) if you know that concentration of (N2O4) at equilibrium = 0.075 M what is the kc for the rxn ?? 2 NO2 → N2O4 ←
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    What is the relationship between electric force and distance between particles?

    - the electric force is inversely proportional to the square of the separation r between the particles and directed along the line joining them. - is proportional to the product of the charges q1 and q2 on the two particles. i don't understand wut does that mean, can someone please...
  3. M

    Block pushed up frictionless incline

    a block is pushed up a frictionless 30 incline by an applied force the force F=50 N and the mass = 3 kg whats the magnitude of the resulting acceleration of the block ? sol: -Fcos30=ma mg+Fsin30=ma right answer for a=9.4
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    Calculating Force Needed to Move 4.8 kg Block Against Wall

    but the correct answer is 63.2 ! never mind close enough :) lool u must hate me now thx alooooooooot ur the best
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    Calculating Force Needed to Move 4.8 kg Block Against Wall

    Fcos37=n Fsin37+ 0.2n - mg=0 5 Fsin37 + n -235.2 = 0 Fcos 37 - n =0 F(5sin37+cos37)=235.2 F=61.7
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    Calculating Force Needed to Move 4.8 kg Block Against Wall

    blochwave said Fgrav+Ffr-F*sin37=0, or F*sin37-Fgrav-Ffr=0 thats why i changed my answer and put negative signs to both Ffr and weight weight=mg=n
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    Calculating Force Needed to Move 4.8 kg Block Against Wall

    Fsin37-0.2n-n=0 Fsin37= 1.2(Fcos37) ?
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    Calculating Force Needed to Move 4.8 kg Block Against Wall

    here is wut i did: Fsin37+0.2-mg=0 Fcos 37 =n F ( cos37+sin37) = 93.88 F = 67
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    Calculating Force Needed to Move 4.8 kg Block Against Wall

    the first equation Fsin37+0.1+mg=0 the vertical forces acts upward because its abt to slip down right ?
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    Calculating Force Needed to Move 4.8 kg Block Against Wall

    i think its above horizontal but even when i add them up the answer is wrong and by solving Fcos37=n the answer of F is wrong too !
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    Calculating Force Needed to Move 4.8 kg Block Against Wall

    a block of mass 4.8 kg is pushed up against a wall by a force F that makes 37 angle with the horizontal. the coefficients of static and kinetic friction are 0.2 and 0.1 respectively. the magnitude of the force F in N that makes the block just about to slip down: wut i did is: F sin...
  12. M

    Vertical and horizontal asymptotes of the curve

    vertical and horizontal asymptotes of the curve of f(x) = (x^2+x-6)/(9-x^2 ) are respectively : a) x=3,x=-3,y=-1 b)x=3,y=-1 c)x=3,y=1 d)x=-3,y=-1 i did the infinit limit to find the horizontal asymptote and i got -1 then to solve the vertical; 9-x^2 = 0 and...
  13. M

    Limit as x-> 4 of 3-x / x^2-2x-8

    lim 3-x / x^2-2x-8 x-> 4- the answer is + infinit
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    Finding One-Sided Limits: The Simplest Way

    can u give me an example ?
  15. M

    Finding One-Sided Limits: The Simplest Way

    heey, i know how to find limits but i can't find limits from the left and from the right can someone pleasezzzz show me the simplist way to do it thx
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