Honestly, this is an entire new method to solve for me. And I love it! I will ask my teacher if this method is usable. Thanks a lot for everyone's help all those time!
Given a,b,c > 0 satisfying 1/(1+a) + 1/(1+b) + 1/(1+c) >= 2. Prove that abc <= 1/8This is the full problem. This one is just my attempt for this full problem, and it is incorrect. Sorry for making some of you lose some braincells unnecessarily.
Thanks for caring and for publishing this interesting post... But it seems to be indeed out of my knowledge and the range of knowledge I am allowed to use.
I would really appreciate if someone could solve it with a method that suits me better.
Honestly, I think there's something with this line:
$ 2 >= \sqrt[3]{\frac{1}{abc}}$
This >= 6
1/3 this >= that (this >= 3that)
It doesn't mean 1/3 × 6 >= that.
this >= 6 and this >= 3that doesn't mean 6 >= 3that or 6 >= 3that.
I forgot to mention a,b,c are positive numbers too
Thanks a ton for...