Recent content by mrdummy

thanks a lot for all your help

ohh okay i c what u mean but if the x and y on both r diff how r they still forming a 90 degree angle at the point they meet on the object

so can you please give me a clear answer please please !

ok i m confused y say the x and y are equal but the xs are not ?

yah i know that the force due to gravity ( or the tension in y direction) is diff for both strings but isn't the tension in x direction same and i think the tension in x direction is the centripetal force on the object which is also in the x direction which is 790 N

please can you give me the answer i m starting to get annoyed by the question

why wouldn't the tension in the x direction for both the strings be the same.. they both r connected to the same pole

its the y component of tension that will cause a change in tension in each of the strings

dont they equal each other they both r in the same direction

so r u saying momentum is not conserved

but how do i find y tension is upper string and y tension in lower string

yes u r right US - LS = Fg

this is easy in any physics equation especially these kinds u have to use the equation p = mv right = pos...left = - momentum = mass * velocity starting momentum = 2 * 4 = 8 and p = 1 * -12 total P = 8 - 12 p = -4 this has to be the ending momentum too due to the law of conservation of...

no no look at the picture the y component of tension in the upper string ( US Y ) equals the y component of tension in the lower sting ( LS Y ) and the force pulling the weight down which is mg which is 50 N US Y = LS Y + 50 N

yah you are right i am blank i understand that the tension in each string is the hypotnuse of a 90-45-45 triange but i still can't get my head around how do i got about finding it