Homework Statement
http://prntscr.com/7rw2hj
Homework Equations
deformation = PL/AE
A= pi/4 (d^2)
The Attempt at a Solution
The displacement of the shaft is equal to the summation of the displacement of each individual piece. I started on end A, and got the internal force to be 6kips
then...
sorry about that i will keep it in mind for next time!
I do think that these illustrations are hard to understand but i did gather that there are two unknown torques since its fixed on both ends. I guess (if my reply above is sound) that i wasnt able to bridge the last part of the problem, that...
This does make sense. What i meant by the net torque being 300N-m is the torque applied.
So if the torque experienced at fixed end B is 645N-m, and the applied torque is 300, then it follows that the torque at A must be something such that the net torque equals zero.
Thus 345 N-m.
is this logic...
Homework Statement
http://prntscr.com/7rtrep
http://prntscr.com/7rts95
Homework Equations
theta = TL/GJ
t(max)= Tc/J
The Attempt at a Solution
The two questions i have are rather similar so i put them up at the same time, i hope that's okay.
For the first one ( the first link) i started by...
BvU, my apologies for not expressing things cleary enough
so i did (300)(.6) +(100)(1.2) for the initial momentum of the first cart and the rock, which gives
300 = Mc1Vc + MrVr
so 300=(Mc1+Mr)Vf
300/(Mc1+Mr) = Vfx
Vfx=.75m/s
As for the equation, aleph, are you saying that the coefficient of...
1. The problem statement, all variables and given/own data
http://prntscr.com/661d5d
Homework Equations
m1v1 + m2v2 = m1v1p +m2v2p
The Attempt at a Solution
I asumed that the momentum in the y direction is constant, and that in the x direction it is conversved.
Also, i thought of it as 2 parts...
Homework Statement
http://prntscr.com/5aj6fz
Homework Equations
Efy=0
Efx=0
EM=0
The Attempt at a Solution
I drew a FBD and assigned x and y components at A. There is a normal force at B and F and M are known. I took this to mean that there are 3 unknowns in the problem, which should be able...
the Mg would be greater since it is accelerating downwards, right? I think i grasp it now, the acceleration depends on the net force, so the placement of the variables in the formula is determined by the motion of the object.
So the motion force comes first in the equations? is this a...
Homework Statement
So the question revolves around two blocks, one of mass A and one of mass B. The Mass A block is on a smooth horizontal surface, connected by a thin chord that passes over a pulley to the second block, of Mass B. The question asks to draw a free body diagram of both objects...