Recent content by mrowa196

I used this diagram and potential divider calculations to get the voltage at A and B and that gave me a good result At point A: 5.6/(5.6+3.3)*6.2 = 3.90 At point B: 2.7/(68+2.7)*6.2 = 0.24 The difference would be 3.66. Correct?

Thank you all very much! I understand it completely now ;)

How about R3 being in parralel with R4, but in series with R2 and R5 in parralel? That gives me something about 4.5 after quick calculation.

I still see it as in the beginning: R4 and R5 are in series and parallel to R2 and R3 which are in series :/

Great, that diagram of yours explains everything about the voltage. The method for determining the Thevening resistance from my lecture notes is here: In the original circuit there is voltage source on the left, so you ignore it, look at the circuit from the right and then 6 Ohm is in series...

How about the resistance? I've had this: But despite good result it must be wrong, because it shouldn't be 6.8 but 68 kOhms.

:)) Could you please walk me through your calculations?

Yes, you're right, I've actually went through my notes and there is 68000 kΩ written but I've crossed one 0, because I could not get theoretical value of Thevenin resistance close the he experimental one otherwise... Did you get it? Experimental data:

12 V

0.8 mA

I found the photo of the circuit.

Yes, I have. The resistances must be correct because theoretical and experimental values of resistances are almost identical.

Reading from the colour codes. That was checked - they are correct.

It's actually a lab report, so it's a whole document, but it's only one part of it - maximum power transfer.

What if I ignored R3 and R4 part of the circuit and I would be left with: Then I ignore R1 and 15 V source part and I would be just left with 6.2 "source" let's say and two resistors circuit. Then, using voltage dividor rule and the values of resistances of the resistors (5.6/(5.6+3.3))*6.2...