Recent content by msc8127

6.626 x 10^-34 Js is actually Planck's constant. I tried that and I get the correct order of magnitude, but instead of getting 180pm i get 290pm...the number posted in the original post is Plancks constant converted to eV (which I'm sure you already knew) Either form of Planck's constant that...

Homework Statement an electron is moving at 2.5 x 105m/s. Find the electron's De Broglie Wavelength. Homework Equations De Broglie relates wavelength of electron waves to momentum of the electron by lambda = h/p where h is Planck's constant. The Attempt at a Solution given the...

Homework Statement determine whether rolle's theorem can be applied to f on the closed interval [a,b]. If Rolle's theorem can be applied, find all values of c in the open interval (a,b) such that f'(c) = 0 Homework Equations f(x) = (x-1)(x-2)(x-3) with the interval being [1,3] The...

i'm not sure why I'm letting this stuff get the best of me. There are other topics later in the same chapter that should be more complex, but for some reason this simplification stuff has had my number. on a side note, I quit college in 2003 (1 semester from Music Ed degree) and have been in...

ok, I've worked through the problems we've went over so far and though I had everything figured out, then another curve ball got me. the problem I'm working on now is: y= x[(1-x2)1/2] I applied the product rule and applied the chain rule to get to: y`= x[(1/2)(1-x2)-1/2(-2x)] +...

excellent...Thank you all for guiding my fumbles through the simplifications. I'll rework these examples a few times and make sure they're in my head the right way. Thanks again for the help

argh... trying again from the chain rule: (x)[9(3x-7)^2] + (3x-7)^3 = (3x-7)^2 * (12x-7) If that's not correct, then i can't figure out where I'm screwing up at. I do see where I was screwing up by not multiplying by the derivative of the "inside" when using the chain rule now...sorry I...

ok, using the chain rule I get f`(x) = [(x)(3)(3x-7)^2] +(3x-7)^3 which if I take out (3x-7)^2 from both terms, I am left with (3x-7)^2 * [(3x)*(3x-7)] From there I can take out a 3x from inside the brackets and get: [(3x)*(3x-7)^2] * (-7) = f`(x)??

no problem! Here's what I did: f(x) = x(3x-7)^3 So via product rule I get: f`(x) = (x)(3)(3x-7)^2 + (1)(3x-7)^3 = (3x-7)^2 * (6x-7) With my luck something there isn't correct, but that's how I worked the problem. Thank you!

I see where you all are getting the solution now I think. The next similar example in the textbook is: f(x) = x(3x-7)^3 There is no solution for this problem in the back of the text, so if you all could post a solution for me to check what I get against I would really appreciate it...

thank you for the reply... Are you able to factor the 2x out of both sides by using the power rule on the x^2 in the terms [x^2(4(x-2)^3)]? i'm really not sure I understand where the 2x comes from in the first term, or where the 4 goes during the simplification. Sorry, I'm sure I'm...

Homework Statement Find the derivative of the function: f(x) = x^2((x-2)^4) Homework Equations f`(x) = (u)(y`) + (u`)(y) The Attempt at a Solution Via the product rule I got [x^2(4(x-2)^3)] + [(2x)(x-2)^4] the book then goes on to give the solution as 2x(x-3)^3 * (3x-2) I'm...

once again, got to love algebra. Thanks Sara!

ok, one more problem here that I've tried to work. I think I'm ok on it except for the factoring out in the last step. the given problem is f(x)= x(3x-7)^3 I got f '(x) = x[3(3x-7)^2] + (1)(3x-7)^3 via the product rule. after attempting to factor I ended up with f '(x) = (6x-7)(3x-7)^2...

gotta love how algebra mistakes cause more errors than actual cal fundamentals. I was out of school many years, in fact the last math class I had was college algebra in 2001. So, I'm really struggling with stuff that isn't all that difficult in the grand scheme of things. Thank you both...