Recent content by mucky

Sooooo... Circular radius: sin20 x 3.5 = 1.197m Then could I: 2\pi\sqrt{}1.197/9.81tan20 = 3.638s Because I have the period time: 1/f = 1/3.638 = 0.275 revs/per/sec 0.275 x 60 = 16.49rpm message back Formula I received from my tutor was for a similar problem but can't be used in...

Homework Statement 1 A fairground roundabout has a number of carriages hung from a rotating circular roof by means of chains 3.5m long. The upper ends of the chains are attached to the edge of the circular roof which has a diameter of 6m. During operation, the carriages must not exceed an...