Recent content by mysticjbyrd

Anyone got an idea what's up? When I plugged in the answer it told me "Dont forget the energy needed to melt the ice. ?

Homework Statement An insulated beaker with negligible mass contains liquid water with a mass of 0.325 \rm{kg} and a temperature of 69.9 C. How much ice at a temperature of -15.0 C must be dropped into the water so that the final temperature of the system will be 39.0 C? Take the specific heat...

Nah I got it... it looks like "in" on my book, but it is actually natural log. Thanks though

Plot "In distance versus In time" Homework Statement What is "In distance versus In time"... And no it is not just Distance v/s time, because that is part(a) to the question. Homework Equations None The Attempt at a Solution I have no clue what this is supposed to mean...

I am actually using excel to perform the time steps, as you may know from my previous post that was in another thread. I would never attempt to do this by hand, that would be insane and worthless. I am rather new to excel, no experience with programming algorithms or excel macros, and 1...

can anyone else give me some more input? Thanks

can anyone else give me some more input? Thanks

You are using wind relative to the ground and not the ball... The ball won't be traveling anywhere near 1 m/s on z axis

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The diameter of a hydrogen atom is about 5*{10}^{-8)mm.. Which means you increased the size by a few "gazilion" times. You did not mention increasing the size of the hand, because if you did it would actually be the same situation. The hand would be about the size of the planet and the atom...

can anyone else give me some more input? Thanks

Yah I was still in the process of editing it Andrew. I am new to posting things here and it took me a lot longer than I thought to post the information. I could really use some more input though, thanks.

Homework Statement This is a real world problem and not a problem in a book, so if you feel I am missing some information just let me know. A ball is flying at 25 m/s The wind is blowing perpendicular to the trajectory at .44704 m/s \rho = \frac{1.17 kg}{{m}^3} Cd = 1/2...

That is like trying to compare a giant fishing net to a coffee filter... The coffee filter has little holes that allow the water to pass through, but prevents the coffee grounds. Now if you drastically increased the size of the coffee filter it would be the size of a large fishing net...

Ok so what you are saying is that you have to consider the velocity of the ball from both the X and Z. But what about the velocity of the Y axis as the ball falls? Sorry to be so annoying, I have only had 1 semester of physics thus far, and I appreciate the help.