Recent content by namekyd

ahhh got it, thank you so much

sorry that's what i meant for b

Perhaps I am misunderstanding the way to solve the problem here. In my mind I would a) show that Inf{ f(x) + g(1-x) } >= inf{f(x)} + inf {g(1-x)} b) show that g(1-x) = g(x) for the domain [0,1] and hence that Inf{ f(x) + g(1-x) } >= inf{f(x)} + inf {g(x)} I don't know how to show (a)...

I'm having a bit of trouble with it. I know that I can use the triangle inequality to say that |f(x) + g(1-x)| <= |f(x)| + |g(1-x)| I am unsure as to how to proceed from there, I have been thinking perhaps using the Completeness Property to say that |f(x)| + |g(1-x)| >= -[f(x) + g(1-x)] but...

I Just started Analysis 1 this week and I've encountered some tricky problems in the Assignment Homework Statement Let f,g : [0,1] -> R be bounded functions. Prove that inf{ f(x) + g(1-x) : x (element of) [0,1]} >= inf{f(x) : x (element of) [0,1]} + inf{g(x) : x (element of) [0,1]}...