Wow I was really not understanding but now really am!
Oh and i was confused at the notation i thought the square brackets were abs value bars but they're brackets :smile:
Thank you so much for your help!
Ok well...
(f+g)(a)=f(a)+g(a) i have no idea i want to say distributive property?
f(a)+g(a)= f(b)+g(b) because of the limitations in the question right? if they both have to come to the same solution.. f(a)=f(b) then g(a)=g(b). For some reason all i can think about is extreme value theorem...
Oh I understand we can just name two functions since U represents the set of functions...
well (f+g)(a) would = (f+g)(b) and would be equivalent to f(a)+g(a)=f(b)+g(b)? I'm not really sure if I'm right about that.
then c*f(a)=c*f(b)..
I understand the point of what's happening but not the...
Homework Statement
Is U={f E F(\left|a,b\right|) f(a)=f(b)} a subspace of F(\left| a,b \right|) where F(\left| a,b \right|) is the vector space of real valued functions defined on the interval [a,b]?Homework Equations
I know in order for something to be a subspace there are three conditions...