Recent content by nbrady

Yeah, it's a ping pong ball and that mass was given Thank you so much, everybody! I finally get it!

Ok...NOW let me see if I understand this. I had to read your post a couple of times, because I suck at physics. On the way down, the ball has PE which would be mgh = 0.0027 * 9.8 * 0.5 meters (it was dropped from this height) = 0.01323 J. The PE gets converted to KE as it falls (before it...

Let me see if I understand this, based on your third paragraph. The PE at 0.5 meter (because that what I had to measure first) would be (mgh) 0.0027 kg * 9.8 m/s^2 * 0.5 meters = 0.01323 J. KE before the bounce would be 0 because it hasn't bounced yet. The potential energy at the max height...

Would v and y be equal??

Sorry everyone, Thank you for trying to help me. Let me try this again. This was the procedure to my lab: Find a room with a hard, flat surface that you will be able to drop a ball on. Hint: The harder the surface the better. Using the tape measure, measure 0.50 meters above the flat...

Hi everyone! Thank you for having me here! Nicole

Homework Statement Ball mass = 0.0027 kg PE (0.5 meters) = 0.01323 J height of ball after three trials = 0.19 meters KE before bounce = 0.01323 J PE at new max height = 0.00503 Total energy = KE + PE Ke after bounce = ? Homework Equations mgh The Attempt at a Solution I did a lab where I...