Recent content by NCStarGazer

I actually purchased this book about three months ago, my plan was to go through it this summer. I am now finishing Calculus III and I didn't want to jump into the book before I was ready for it and become discouraged (I also have Wheeler's book, got it a great price at the same time, but it is...

Awesome, I see it with better understanding. I know Maxwell's equations and I understand the Lorenz transformation. I was trying to figure out where the attraction comes from in Relativity. We really don't know at present and that is cool, gives a good study in one's spare time. Do you...

Relativity, Gravity, "Attraction", Curved Space Okay, I am by no means knowledgeable in this field, probably more dangerous than anything. But I have a question about gravity. If two masses are identical (in an idea situation) and have no other forces acting on them, and start from a...

I have a need to know how fast gas bubbles will travel from a variable depth in a liquid to the surface. I realize there are a lot of variables here, liquid density, gas density, temp. etc... What I need is a general guideline for calculating the time with different gases through a homogenesis...

D H Thanks, I see how the center of mass can bring clarity. In working with your post I am still having trouble getting \frac{GMm}{r^2}= \left(\frac{2\pi}{\tau}\right)^2\frac{M}{M+m}\,r To yield your answer, I placed it in Maple and it always returns a version that has Gm(M+m); not...

Well... I am confused, as the link you reference has 4π2a3 = P2G(M + m) under "Conversions for Unknowns", which is the same as what I referenced (M+m)*P^2 = (4*pi^2*a^3)/G.

Looking at the gravitational equation F=G*(M*m)/r^2 and centripetal force F = ((V^2)/r)*m If you set the two equal and solve for G you get: G = ((V^2)*r)/M Substituting (4*pi^2*r^2)/T^2 for V^2 you now have G = (4*pi^2*r^3)/(M*T^2) With solution for G, look at Kepler's...