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Electric field at a point inside a non-uniformly charged sphere
My solution is this: $$q = \varepsilon_0 \int E.dA$$ Based on gauss's law. Taking the derivative of both sides with respect to $$A$$ we get: $$\frac{dq}{dA} = \varepsilon_0 E$$ From chain rule: $$\frac{dq}{dA} = \frac{\frac{dq}{dr}}{\frac{dA}{dr}}$$ On the other hand: $$q = \int \rho dv = \int...- Necrolunatic
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- Electric field Gauss law Gauss' law Gauss's law
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- Forum: Introductory Physics Homework Help