Recent content by needhelp171

I'm taking a course and I'm having some trouble understanding the concepts. I'm sure, in practice, there will be resistance, but I want to know the behavior of an ideal diode. Sorry if that wasn't clear.

One person says the diode behaves as an open wire while conducting, the other says it doesn't. You say, for a diode, there's a voltage drop across it when it is conducting current?? The other guy said the exact opposite...?

Oops -- meant to say short wire, not open wire! And yeah...if it is a short wire, then the voltage before and after the diode is exactly the same. But the physical properties of a diode demand that it only conduct current if the voltage before the diode is greater than the voltage after -- not...

My understanding is that a diode conducts current if the voltage at its anode is larger than the voltage at its cathode. I don't understand this. 1) Once the diode begins conducting current, the voltages at the anode and the cathode are identical (the diode serves as an open wire). Therefore...

Homework Statement Explain what is happening in the following four circuits: I don't know how to draw the circuits, but they're really really simple: (a) Current source connected in a loop with an inductor (b) Current source connected in a loop with a capacitor (c) Voltage source connected in...

Weird stuff. But thanks a lot for answering my question! You were a ton of help!

So was what I said in post #12 correct? I suppose I had assumed that resistors can't produce or consume power...but they can??

Yes, but in our example (the one of the posted diagram), the current is entering the negative terminal, hence the source is supplying energy...

How does the voltage source absorb power when it increases the potential difference across it?

So...I guess I should use p = vi Power for voltage source : 10 * 6 = 60 Power for current source : 2 * 6 = 12 Power for resistor: -12 * 6 = -72 60 + 12 - 72 = 0 ...

Well in my drawing I had the resistor and current source flipped from your drawing, with the current from the current source flowing directly into the resistor, though I think it doesn't matter? Anyways, going off your drawing, the voltage source is a supplier because it raises the voltage from...

But I think the situation gets really sticky when you throw in a resistor. So let's say you have, in series, voltage source --> current source --> resistor --> original voltage source (completing the loop) Let the voltage source be 10v, the current be 6 amps, and the resistor be 2 ohms...

Ok I drew it out and I see what you're saying. Thanks! So then if the current source is positive, and it's going into the negative terminal of the voltage source, then the voltage source must be supplying energy, which then means that the current source is absorbing energy.

I don't know how to draw a circuit on this site... But when I apply the circuit laws I think there'd be a contradiction because there's no resistor to get rid of the energy (like how you can't just have a voltage source with no resistor because voltage would change without any energy being...

This is more of a theory question than a homework question...but could a circuit consist solely of a voltage source and a current source? What I mean is a very simple circuit with a voltage source of Vx and a current source of Ix, connected in series. No resistor anywhere. Could this work? And...