Assuming this is correct, how do I perform Continuity Correction on this problem. I am not exactly sure how this works.
From what I am aware, you have to add .5 to the discrete value. Is this right?
A coin that is balanced should come up heads half the time in the long run. The population for coin tossing contains the results of tossing the coin forever. The parameter p is the probability of a head, which is the proportion of all tosses that give a head. The tosses we actually make are a...
On a production line, only 45% of items produced meet quality standards. A random sample of 500 items will be taken. Using the normal approximation to the binomial distribution, approximate the probability that less than half of the sampled items meet quality standards.
500*.5 = 250...
Test scores on a standardized test have mean 55 and variance 64. What is the probability that a random sample of 256 scores will have a sample mean score between 53 and 57
I attempted the problem and came up with this:
u=55 and sd = 8 (Square root of 64)
\mu=55 \sigma=\sqrt{64}=8
P(53<...
Let X and Y be the per dollar return of 2 stocks. Suppose that both have an expected return of 0.05, both have a variance of 0.0009 and covariance(X,Y)= -0.001. Suppose that you invest $50 in the stock with return X and $100 in the stock having return Y
1) Calculate the expected return of...
Alright, so the initial probability for Michael is .5 because it is either blue or green. Now Michael's action makes you believe probability of pulling out red ball is 4/9
Stuck on this question:
Suppose you know that there is an urn with 10 balls inside: 5 blue and 5 green. You believe each ball is equally likely to be drawn from the urn. Michael takes out one of the balls at random but doesn't show you which one. What probability should you assign to pulling...
I think I finally got the first part of the problem, but I don't see what exactly the second part is asking...
1. Given that exactly one bullet hit the target, what is the probability that it was Mike's bullet?
P(Ray hit, Mike miss) = .7 * .6 = .42
P(Ray miss, Mike hit) = .4*.3 = .12
P(ray...