Recent content by Nekomimi

OK. Thank you very much, anyway!

Don't you mean multiplying by ##5^{-\frac{2}{3}}##? In any case, yes, I skipped that step because it was previously mentioned. I'll keep that in mind for the next time, though. Since it is solved, is there a way to close this thread?

Oh, I think I get it now. Your tip was for solving it through the way I initially started with? (That is, by not simplifying ##5^{\frac{5}{3}}##.) Well then, let's see: $$ \frac{5^{-\frac{1}{3}}}{5} = \frac{1}{5 \cdot 5^{\frac{1}{3}}} = \frac{1}{5 \cdot 5^{\frac{1}{3}}} \cdot...

I don't understand where I should do that. Was my last try incorrect?

Right, so $$\frac{5^{1/3}}{5 \cdot 5^{2/3}} \cdot \frac{5^{\frac{1}{3}}}{5^{\frac{1}{3}}} = \frac{5^{\frac{2}{3}}}{5 \cdot 5} = \frac{5^{\frac{2}{3}}}{25}$$ Is that right? I'm sorry for the mistake, English is not my first language.

Express the following as a fraction with rational denominator: $$\frac{5^{\frac{1}{3}}}{5^{\frac{5}{3}}}$$ If I try to start by multiplicating both the numerator and denominator by ##5^{-\frac{2}{3}}##, I get: $$\begin{align} \nonumber \frac{5^{\frac{1}{3}}}{5^{\frac{5}{3}}} & =...