A 350KG sailboat has an acceleration of 0.62m/s^2 at an angle of 64 degrees north of east. Find the magnitude and direction of the net force that acts on the sailboat.
I drew out the diagram, but it's just not coming to me.
Thanks for any help
My answer for some reason, comes out completely different from what the book says. Could somebody please do out the work for the first particle?
Here is my work:
F = (8.99*10^-9) (48*10^-6) (70*10^-6) / 0.35^2
which comes out to be: 2.46*10^-16
then F = (8.99*10^-9) (70*10^-6)...
I need somebody to explain to me specifically "Forces of changed particles & Coulomb's Law", which was covered in a class I missed yesterday.
Basically, I know that 8.99 x 10^-9 is a constant used in the beginning of the equation, and then after you put (q1 and q2), which i have no clue what...